81r^2-6=19

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Solution for 81r^2-6=19 equation:



81r^2-6=19
We move all terms to the left:
81r^2-6-(19)=0
We add all the numbers together, and all the variables
81r^2-25=0
a = 81; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·81·(-25)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-90}{2*81}=\frac{-90}{162} =-5/9 $
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+90}{2*81}=\frac{90}{162} =5/9 $

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